Problem

Table: Employee

1
2
3
4
5
6
7
8

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| employee_id   | int     |
| team_id       | int     |
+---------------+---------+
employee_id is the primary key (column with unique values) for this table.
Each row of this table contains the ID of each employee and their respective team.

Write a solution to find the team size of each of the employees.

Return the result table in any order.

The result format is in the following example.

Examples

Example 1

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27

Input: 
Employee Table:
+-------------+------------+
| employee_id | team_id    |
+-------------+------------+
|     1       |     8      |
|     2       |     8      |
|     3       |     8      |
|     4       |     7      |
|     5       |     9      |
|     6       |     9      |
+-------------+------------+
Output: 
+-------------+------------+
| employee_id | team_size  |
+-------------+------------+
|     1       |     3      |
|     2       |     3      |
|     3       |     3      |
|     4       |     1      |
|     5       |     2      |
|     6       |     2      |
+-------------+------------+
Explanation: 
Employees with Id 1,2,3 are part of a team with team_id = 8.
Employee with Id 4 is part of a team with team_id = 7.
Employees with Id 5,6 are part of a team with team_id = 9.

Solution

Method 1

Code

1
2
3
4
5
6
7

SELECT em.employee_id,
       sub.total team_size
FROM Employee em
JOIN (
  SELECT team_id, COUNT(*) total
  FROM Employee
  GROUP by team_id) sub ON sub.team_id = em.team_id;
 
1
2
3

SELECT employee_id, 
    COUNT(team_id) OVER(PARTITION BY team_id) AS team_size
FROM Employee