Output: [1,1,1] Explanation: Let's look at each `wordsQuery[i]` separately: * For `wordsQuery[0] = "cd"`, strings from `wordsContainer` that share the longest common suffix `"cd"` are at indices 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3. * For `wordsQuery[1] = "bcd"`, strings from `wordsContainer` that share the longest common suffix `"bcd"` are at indices 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3. * For `wordsQuery[2] = "xyz"`, there is no string from `wordsContainer` that shares a common suffix. Hence the longest common suffix is `""`, that is shared with strings at index 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3.

Example 2

 
Input: wordsContainer = ["abcdefgh","poiuygh","ghghgh"], wordsQuery =
["gh","acbfgh","acbfegh"]
 
Output: [2,

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