that taking the first 5 was a winning move for Alice, so we return true.

Example 2:

Input: piles = [3,7,2,3]
Output: true

Solution

Method 1 - Alice always wins

The problem involves a game theory scenario where Alice and Bob play optimally with piles of stones. The key insights here are:

Number of piles is even.
Total number of stones is odd, ensuring no tie.
Optimal play by both Alice and Bob.

Since the number of piles is even and both play optimally, it defaults mathematically that the starting player (Alice) always has a winning strategy. Here's a step-by-step reasoning for why Alice always wins:

Since Alice can always choose either the first or the last pile, she can see all piles and predict the results of future moves.
With an even number of piles, Alice can always choose a strategy that leaves Bob in a situation where Bob cannot influence the majority of high-value piles due to their alternate turn structure.

Given the constraints provided, Alice can always take an approach to ensure she ends up with more stones than Bob. Thus, the result of the function should return true.

Code

[{"language":"Java","code":"public class StoneGame {\n    public static boolean stoneGame(int[] piles) {\n        // Alice always wins with optimal play due to even number of piles and\n        // odd total of stones\n        return true;\n    }\n}","lang":"java","html":"<pre class=\"shiki shiki-themes github-light github-dark\" style=\"background-color:#fff;--shiki-dark-bg:#24292e;color:#24292e;--shiki-dark:#e1e4e8\" tabindex=\"0\"><code><span class=\"line\"><span style=\"color:#D7

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