Incomplete

Freedom Trail Problem Problem In the video game Fallout 4, the quest “Road to Freedom” requires players to reach a metal dial called the “Freedom Trail Ring” and use the dial to spell a specific keyword to open the door. Given a string ring that represents the code engraved on the outer ring and another string key that represents the keyword that needs to be spelled, return the minimum number of steps to spell all the characters in the keyword. ...

There is no diffeence in circular list stack and non circular list stack. The insertion, deletion operation takes place in the same place. So it won’t create any modification in the circular list. Here is the implementation of circular stack in CPP Program in cpp #include <iostream.h> #include <stdlib.h> using namespace std; struct node { int info; struct node \*next; }; int c=0; struct node \*top;int empty() { return((top == NULL)? 1:0); } void print() { int i =0; struct node \*temp; cout<<"\\n\\t\\t"; if(c==0) cout<<"\\n\\t\\tNo elements\\n"; else { temp = top->next; while(i!=c) { int info = temp->info; cout<<info<<" "; temp=temp->next; i++; } cout<<"END PRINT"; } } void push(int n) { struct node \*p; p=new node; if(p!=NULL) { c++; p->info=n; if(empty()) top=p; else p->next=top->next; top->next=p; } else cout<<"Not inserted,No memory available"; } int pop() { c--; struct node \*temp; int x; temp=top->next; x=temp->info; if(temp==top) top=NULL; else top->next=temp->next; free(temp); return(x); } int main() { int s,n; cout<<"\\n\\t\\tCIRCULAR STACK IMPLEMENTATION\\n"; while(1) { cout<<"\\n\\t\\t1>Push\\n"; cout<<"\\t\\t2>Pop\\n"; cout<<"\\t\\t3>Print\\n"; cout<<"\\t\\t4>Exit\\n"; cout<<"\\t\\tEnter your choice:"; cin>>s; switch(s) { case 1: cout<<"\\n\\t\\tEnter the number:"; cin>>n; push(n); break; case 2: if(empty()) { cout<<"\\n\\t\\tStack underflow\\n"; } else { n=pop(); cout<<"\\n\\t\\tThe pop value is:"<<n; } break; case 3: print(); break; case 4: exit(1); break; } } } ```Let us know your feedback. ...