Search in Rotated Sorted Array 2 - Check if number exists - Duplicates allowed

Problem There is an integer array nums sorted in non-decreasing order (not necessarily with distinct values). Before being passed to your function, nums is rotated at an unknown pivot index k (0 <= k < nums.length) such that the resulting array is [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], ..., nums[k-1]] (0-indexed). For example, [0,1,2,4,4,4,5,6,6,7] might be rotated at pivot index 5 and become [4,5,6,6,7,0,1,2,4,4]. Given the array nums after the rotation and an integer target, return true if target is in nums, or false if it is not in nums. ...

Find rotation count in rotated sorted array

Problem Question : Find the minimum element in the rotated sorted array. Example Example 1: Input: nums = [5, 7, 9, 1, 3] Output: 3 Explanation: The original array was [1, 3, 5, 7, 9] rotated 3 times. ...

Find Minimum in Rotated Sorted Array 1 - No duplicates allowed

Problem Find the minimum element in the rotated sorted array. For example, the array a = [0, 1, 2, 4, 6, 8, 10] might become: [8, 10, 0, 1, 2, 4, 6] if it was rotated 2 times. [4, 6, 8, 10, 0, 1, 2] if it was rotated 4 times. Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]]. ...

Find Minimum in Rotated Sorted Array 2 - Duplicates allowed

Problem Follow up for “Find Minimum in Rotated Sorted Array”: What if duplicates are allowed? Would this affect the run-time complexity? How and why? This is follow up of - Find Minimum in Rotated Sorted Array 1 - No duplicates allowed Examples Example 1: Input: nums = [1,3,5] Output: 1 ...

Search in Rotated Sorted Array

Problem Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., [0, 1, 2, 4, 5, 6, 7] might become [4, 5, 6, 7, 0, 1, 2]). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. Follow up: what if duplicates are allowed? ...

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