Trie

Problem In English, we have a concept called root, which can be followed by some other word to form another longer word - let’s call this word derivative. For example, when the root "help" is followed by the word "ful", we can form a derivative "helpful". Given a dictionary consisting of many roots and a sentence consisting of words separated by spaces, replace all the derivatives in the sentence with the root forming it. If a derivative can be replaced by more than one root, replace it with the root that has the shortest length. ...

Problem Implement an autocomplete system. That is, given a query string s and a set of all possible query strings, return all strings in the set that have s as a prefix. For example, given the query string de and the set of strings [dog, deer, deal], return [deer, deal]. Hint: Try preprocessing the dictionary into a more efficient data structure to speed up queries. Solution Method 1 - Using Trie with map of children and DFS Trie Class We have already seen Map-based Trie Implementation, and also seen another implementation of trie here: Implement Trie Problem. ...

Problem A trie (pronounced as “try”) or prefix tree is a tree data structure used to efficiently store and retrieve keys in a dataset of strings. There are various applications of this data structure, such as autocomplete and spellchecker. Implement the Trie class: Trie() Initializes the trie object. void insert(String word) Inserts the string word into the trie. boolean search(String word) Returns true if the string word is in the trie (i.e., was inserted before), and false otherwise. boolean startsWith(String prefix) Returns true if there is a previously inserted string word that has the prefix prefix, and false otherwise. Examples Example 1: ...

Problem Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. Examples Example 1: Input: s = "leetcode", wordDict = ["leet","code"] Output: true Explanation: Return true because "leetcode" can be segmented as "leet code". Example 2: ...

Problem Design a data structure that supports adding new words and finding if a string matches any previously added string. Implement the WordDictionary class: WordDictionary() Initializes the object. void addWord(word) Adds word to the data structure, it can be matched later. bool search(word) Returns true if there is any string in the data structure that matches word or false otherwise. word may contain dots '.' where dots can be matched with any letter. Examples Example 1: ...

Here is the Java trie implementation, that we can use for many problems. First thing we need is TrieNode, which represents the individual node structure. The collection of these trienodes can be used to create Trie. TrieNode Class When implementing a dictionary, store the corresponding value in final nodes, and null in non-final nodes. Also, we don’t need to store the char content anymore, as it is now part of map. ...